Description

To reverse a number
Step 1: Take a variable sum assign it to 0.
Step 2: Follow step 3 to step 5 until number is greater than 0.
step 3: Find modulus(remainder).
step 4: Multiply sum to 10 and add remainder to it and assign to sum variable.
step 5: Divide number by 10 and assign to number variable.
step 6: Exit.

C/C++

/* C Program to reverse a number */
//Save it as ReverseNumber.c

#include<stdio.h>
int main(){

    int number, sum=0, remainder, temp;

    printf("Enter a number : ");
    scanf("%d",&number);

    //Assign number of temporary variable to retain it's value
    temp = number;

    while(number > 0){
        remainder = number % 10;

        sum = ((sum * 10) + remainder);

        number /= 10;
    }

    //assign the value of temp variable to number variable
    number = temp;

    printf("The reverse of %d is %d",number,sum);

    return 0;
}

Input:
Enter a number : 
5249

Output:
The reverse of 5249 is 9425

Java

/* Java Program to reverse a number */
//Save it as ReverseNumber.java

import java.io.*;
import java.util.Scanner;

public class ReverseNumber {

    public static void main(String[] args) {

            Scanner scanner = new Scanner(System.in);
        
            int number, sum=0, remainder, temp;

        System.out.println("Enter a number : ");
        number = scanner.nextInt();
        
            //Assign value of number variable to temporary variable to retain it's value
            temp = number;
         
        while(number > 0){
            remainder = number % 10;

            sum = ((sum * 10) + remainder);

            number /= 10;
        }
        
            //assign the value of temp variable to number variable
            number = temp;

        System.out.println("The reverse of "+number+" is "+sum);
    }
}

Input:
Enter a number : 
5249

Output:
The reverse of 5249 is 9425

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