Description
To find the smallest element of an array, Assume any element of array as smallest. Here assuming first element as smallest. Now compare every elements of array to first element. If array element is less than element which assumed as smallest, update the smallest element to that element.
C/C++
/*C program to print smallest element of the array*/ //Save it as PositionOfSmallestNumber.c #include<stdio.h> int main(){ int i,n; printf("Enter the size of array : "); scanf("%d",&n); int arr[n]; printf("Enter the elements of the array : "); for(i=0;i<n;i++) { scanf("%d",&arr[i]); } /*Assuming first element is smallest*/ int min = arr[0]; int pos = -1; for(i=0;i<n;i++) { if(arr[i] < min) { min = arr[i]; pos = i; } } printf("The smallest elements is : %d\n", min); printf("Position of smallest element is : %d", (pos+1)); }
Input: Enter the size of array : 5 Enter the elements of the array : 6 1 2 8 3 Output: The smallest elements is : 1 Position of smallest element is : 2
Java
/*Java program to print smallest element of the array*/ //Save it as PositionOfSmallestNumber.java import java.io.*; import java.util.Scanner; public class PositionOfSmallestNumber { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.println("Enter the size of array : "); int n = scanner.nextInt(); int arr[] = new int[n]; System.out.println("Enter the elements of the array : "); for(int i=0;i<n;i++) { arr[i] = scanner.nextInt(); } /*Assuming first element is smallest*/ int min = arr[0]; int pos = -1; for(int i=0;i<n;i++) { if(arr[i] < min) { min = arr[i]; pos = i; } } System.out.println("The smallest elements is : " + min); //Since index starts from 0, print position as pos+1 System.out.println("Position of smallest element is : " + (pos+1)); } }
Input: Enter the size of array : 5 Enter the elements of the array : 6 1 2 8 3 Output: The smallest elements is : 1 Position of smallest element is : 2
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