Description

Follow the below program to find square root of a number without using
standard library function - sqrt()

C/C++

/* C Program to calculate square root of a number without using 
standard library function - sqrt() */
//Save it as SquareRootOfNumber.c

#include<stdio.h>
int main()
{
    int n;
    float i;

    printf("Enter a number : ");
    scanf("%d",&n);

    for(i=0.00000;i*i<n;i+=0.00001);

    printf("The square root of %d is %f",n,i);

    return 0;
}

Input:
Enter a number : 24

Output:
The square root of 24 is 4.8989863

Java

/* Java Program to calculate square root of a number without using 
standard library function - sqrt() */
//Save it as SquareRootOfNumber.java

import java.io.*;
import java.util.Scanner;

public class SquareRootOfNumber {

    public static void main(String[] args) {

        Scanner scanner = new Scanner(System.in);
        
        System.out.println("Enter a number : ");
        int num  =scanner.nextInt();
        
        float i;
        
        for(i=0.00000f;i*i<num;i+=0.00001);
            System.out.println("The square root of "+num+" is "+i);
    }
}

Input:
Enter a number : 
24

Output:
The square root of 24 is 4.8989863

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