Description

To form number using entered digit, first declare a variable
assign 0 to it. Next add to this variable by multiplying to 10th
power of index of incoming number.

Example: If entered digit is 1, 2, 3
then,
for 1, index=0 then number = 0 + 1*(10, 0) = 1
for 2, index=1 then number = 1 + 2*(10, 1) = 21
for 3, index=2 then number = 21 + 3*(10, 2) = 321

C/C++

/* C program to print number formed using entered digits*/
//Save it as NumberUsingInputDigit.c

#include<stdio.h>
int main(){

    int i, n;

    printf("Total number of digit you want to enter : ");
    scanf("%d",&n);

    int arr[n];

    for (i = 0; i < n; i++) {
        printf("\nEnter the %d digit : ",(i+1));
        scanf("%d",&arr[i]);
    }

    double num = 0;
    
    
    //Syntax of pow function -
    //double pow(double x, double y)
    
    
    
    /*
    To find the power of int or a float variable,explicitly convert the type
    to double using cast operator.
    */
    
    
    for(i=0;i<n;i++) {
        num = num + (arr[i] * pow(10,(double)i));
    }
    
    /*
    Finally typecast the num to get result in integral value
    */
    
    printf("\nThe number formed is : %d", (int)num);

    return 0;
}

Input:
Total number of digit you want to enter : 
5
Enter the 1 digit : 
2
Enter the 2 digit : 
5
Enter the 3 digit : 
8
Enter the 4 digit : 
7
Enter the 5 digit : 
2

Output:
The number formed is : 27852

Java

/*Java program to print number formed using entered digits*/
//Save it as NumberUsingInputDigit.java

import java.io.*;
import java.util.Scanner;

public class NumberUsingInputDigit {

    public static void main(String[] args) {

        Scanner scanner = new Scanner(System.in);

        System.out.println("Total number of digit you want to enter : ");
        int n = scanner.nextInt();

        int arr[] = new int[n];

        for (int i = 0; i < n; i++) {
            System.out.println("Enter the "+(i+1) +" digit : ");
            arr[i] = scanner.nextInt();
        }
        
        int num = 0;
        
        for (int i = 0; i < n; i++) {
            num = (int) (num + arr[i] * Math.pow(10,i));
        }
        
        System.out.println("The number formed is : " + num);
    }
}

Input:
Total number of digit you want to enter : 
5
Enter the 1 digit : 
2
Enter the 2 digit : 
5
Enter the 3 digit : 
8
Enter the 4 digit : 
7
Enter the 5 digit : 
2

Output:
The number formed is : 27852

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